-0.14x^2+5.6x+11=0

Solution for -0.14x^2+5.6x+11=0 equation:

-0.14x^2+5.6x+11=0

a = -0.14; b = 5.6; c = +11;
Δ = b2-4ac
Δ = 5.62-4·(-0.14)·11
Δ = 37.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.6)-\sqrt{37.52}}{2*-0.14}=\frac{-5.6-\sqrt{37.52}}{-0.28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.6)+\sqrt{37.52}}{2*-0.14}=\frac{-5.6+\sqrt{37.52}}{-0.28}
$